49x^2-24=0

Solution for 49x^2-24=0 equation:

49x^2-24=0

a = 49; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·49·(-24)
Δ = 4704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4704}=\sqrt{784*6}=\sqrt{784}*\sqrt{6}=28\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{6}}{2*49}=\frac{0-28\sqrt{6}}{98}
=-\frac{28\sqrt{6}}{98}
=-\frac{2\sqrt{6}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{6}}{2*49}=\frac{0+28\sqrt{6}}{98}
=\frac{28\sqrt{6}}{98}
=\frac{2\sqrt{6}}{7}
$